Something I use: b = j.cos.items() b.sort(lambda a, b: cmp(b[1],a[1])) # sort by value. [0] would be the key b = b[:50] # get top fifty values j.cos = dict(b) Really badly highlighted with:

source-highlight -spython -fxhtml sort.py

Try use the Basic style sheet?


#!/usr/bin/env python2
""" Explicit dict (mapping type) definition, and method examples to show how to sort the partic. value in the tuple """
results = {
        'tdk'       : (0.0424, 0.0343),
        'td'        : (0.0309, 0.0317),
        'tk'        : (0.0449, 0.0348),
        't' : (0.0301, 0.0308),
        'dk'        : (0.0480, 0.0352),
        'd' : (0.0285, 0.0244),
        'k' : (0.0488, 0.0357),
        }
def sort(dict, item):
   """ This is a typical list comprehension method I use to sort a dict by it's value """
         l = [(v[item], k) for k, v in dict.items()]
         l.sort()
         l.reverse()
         return l
def show(list):
  """ Shows a ranked output of sorted list """
        count = 1
        for i in list:
                value, key = i
                print count,
                print ': ',
                print key,
                print '  \t',
                print value
                count += 1
if __name__ == "__main__":
        show(sort(results, 0))
        print
        show(sort(results, 1))

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